BELLWORK Eureka Module 1 Lesson 25 Problem Set

BELL-WORK Eureka Module 1 Lesson 25 Problem Set 1 a

BELL-WORK Eureka Module 1 Lesson 25 Problem Set 2 b

BELL-WORK Eureka Module 1 Lesson 25 Problem Set 2 d

BELL-WORK Eureka Module 3 Lesson 16 Problem Set 1 ***Solved using the TI calculator

Writing the equation of a parallel line Write an equation for the line that contains (-2, 3) and is parallel to y = 5 x – 4 2 Do you know the slope and a point on the line we are trying to write the equation of? Point (-2, 3) Slope 5 2 So… y = 5 x + b 2 3 = 5(-2) + b 2 b=8 y = 5 x + 8 2

Writing the equation of a parallel line A line passes through (-3, -1) and is parallel to the graph of y = 2 x + 3. What equation represents the line in slope-intercept form? Point (-3, -1) Slope 2 So… y = 2 x + b -1 = 2(-3) + b b=5 y = 2 x + 5

Determining Perpendicular Lines When Given an Equation Are the graphs of y = -¼x – 1 and -4 x + y = 12 perpendicular? Slope 1 = -¼ -4 x + y = 12 y = 4 x + 12 Slope 2 = 4 Therefore the lines are perpendicular.

Determining Perpendicular Lines When Given an Equation Slope 1 = ¾ Slope 2 = 4 3 Neither Slope 1 = -1 6 Slope 2 = -1 6 Parallel

Writing the Equation of a Perpendicular Line Write an equation for the line that contains (6, 2) and is perpendicular to y = -2 x + 7. Slope ½ Point (6, 2) y = mx + b 2 = ½(6) + b b = -1 y = ½x – 1

Writing the Equation of a Perpendicular Line Slope -½ Point (1, 8) y = mx + b 8 = -½(1) + b b = 17 2 y = -½x + 17 2