Bellwork Complete the bellwork in your comp book

Bellwork Complete the bellwork in your comp book or on notebook paper

ESSENTIAL LEARNING FOR THE WEEK: • Combining Like Terms • Variables on Both Sides • Special Cases • Review • Test

People who are twins are considered a “like pair” because they have exactly the same features. 1 Twin + 1 Twin = 2 Twins OR 1 t + 1 t = 2 t

Example: Solve 3 x + 5 x + 4 – x + 7 = 88

Partner Work: You will work with a partner on the following examples. There are two jobs that you will rotate between the two of you. JOB 1: One person writes all the work that is being explained to him/her for one problem. JOB 2: One person explains exactly what to do to solve the problem. After checking the solution, the roles switch on the next problem. Continue switching the roles through each problem until all examples are complete.

Solve -4 n + 7 + 2 n = 1 3(x - 4) + 2 x = 13

Solve: -4(4 x – 8) = -16

§Steps: §Parenthesis (Distribute) §Combine Like Terms §Solve the Two-Step Equation §-5 n + 9 + 3 n = 1 §-2(m + 15) + 8 m = 90

1. Do I have parenthesis? If so, what should I do? 2. When distributing, do I multiply to every term in the equation? 3. After distributing, what do I look for next? 4. What operations are being used when combining like terms? 5. After I have combined like terms what do I need to do? 6. How do I know if my final answer is correct?

Discuss with your partner how to work through 8 x + 3 = 5 x + 12 using the balance beam method.

Solve: 6 x + 7 = 8 x – 13

Partner 1 Partner 2 § 6 r+7=13+7 r § 13− 4 x=1−x § − 7 x− 3 x+2=− 8 x− 8 § − 14+6 b+7− 2 b=1+5 b § − 8 n+4(1+5 n)=− 6 n− 14 § 7(5 a− 4)− 1=14− 8 a § 5 n+6(2+2 n)=4 n+18 § 4 n+7 -2 n=2(4 n-3)

Solve: 7(x + 1) + 3 x = 2 x + 15

§ When any value for can be substituted for the variable and the equations remains true. § 3 x+4=3 x+4 The left side is the exact same as the right § 2(4 x+5)-2 x=4 x+10+2 x

§No matter what is substituted for the variable, the equation will never be true Same variable and coefficient § 2 x+4=2 x+2 Different constant §Ex: 3 x+4 -2=3(x+1)

§ -1(-4 x + 7) = -2 + 4 x § 8(k − 6) + 58 = 2(4 k + 5) § 12 + 4 n = 4(n + 3) § 267 = 5(8 n + 4) + 7 § 4(3 x-2)=12 x-8 § ½(10 x+20)=5 x+8 § 2 x+6 -4 x=-2 x+6 § 2 x+4=2 x-8

Identify as either 1 solution, no solution, or infinite solutions: 7(x + 1) + 3 x = 10 x + 7

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