Area of a Circle Starter Which of these

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Area of a Circle π

Area of a Circle π

Starter • Which of these shapes has the greatest perimeter? Which has the smallest?

Starter • Which of these shapes has the greatest perimeter? Which has the smallest? • What is each perimeter in terms of d? d d d

Starter Answer • Square has 4 sides of length d • Hexagon has 6

Starter Answer • Square has 4 sides of length d • Hexagon has 6 sides of ½d d d ½ d 4 d 3 d d

Starter Answer • Square has 4 sides of length d • Hexagon has 6

Starter Answer • Square has 4 sides of length d • Hexagon has 6 sides of ½d • Circle is between 3 d and 4 d 4 d 3 d πd

Areas • Which of these shapes has the greatest area? Which has the smallest?

Areas • Which of these shapes has the greatest area? Which has the smallest? • What is the area in terms of r? r r r

Areas • Large square is 2 r x 2 r = 4 r 2

Areas • Large square is 2 r x 2 r = 4 r 2 • Small square is half of this = 2 r 2 r r 2 r r

Areas • Large square is 2 r x 2 r = 4 r 2

Areas • Large square is 2 r x 2 r = 4 r 2 • Small square is half of this = 2 r 2 • Circle has area in between 2 r 2 and 4 r 2

Area of a circle • A circle has radius r

Area of a circle • A circle has radius r

Rearrange the sectors

Rearrange the sectors

Consider the lengths So the length of this side is πr Circumference of circle

Consider the lengths So the length of this side is πr Circumference of circle = 2πr Length of half circumference = πr

Consider the lengths So the height is r πr Radius of circle = r

Consider the lengths So the height is r πr Radius of circle = r

Consider the area r πr Area of shape is close to area of parallelogram

Consider the area r πr Area of shape is close to area of parallelogram = base x height = πr x r Hence the area of a circle is = πr 2

Summary r d • A circle has radius r and diameter d • Circumference

Summary r d • A circle has radius r and diameter d • Circumference of a circle C = πd or C = 2πr • Area of a circle A = πr 2 Fiddle-dee-dum, fiddle-dee A ring round the moon is π times d But if you want a hole repaired Then what you need is πr 2.