Aqueous Reactions Dr Ron Rusay Aqueous Reactions There

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Aqueous Reactions Dr. Ron Rusay

Aqueous Reactions Dr. Ron Rusay

Aqueous Reactions There are several general types: 1) Precipitation: An insoluble salt forms from

Aqueous Reactions There are several general types: 1) Precipitation: An insoluble salt forms from the addition of solutions. (Refer to Solubility Rules) 2) Acid-Base Reactions (Neutralization) generally produces a salt plus water 3) Oxidation-Reduction (Redox) there is a change in oxidation numbers between reactants and products

Solution Test Apparatus for Electrolytes

Solution Test Apparatus for Electrolytes

Conductivity

Conductivity

Electrolytes Aqueous solutions can be categorized into 3 types: non-electrolytes, strong electrolytes or weak

Electrolytes Aqueous solutions can be categorized into 3 types: non-electrolytes, strong electrolytes or weak electrolytes based on their ability to conduct electricity. A solution must have ions to conduct. Pure Water does not conduct. Aqueous solutions can be tested for conductivity which will determine the degree of ionization of the solutes. It is possible to have full or partial ionization.

Molarity (M) = Moles solute / Liter solution Electrolytes Almost all ionic compounds and

Molarity (M) = Moles solute / Liter solution Electrolytes Almost all ionic compounds and a few molecular compounds are strong electrolytes. Several molecular compounds are weak conductors, most are non-conductors. Conductivity is directly related to the amount of ionization, i. e. ions in solution. Table salt, sodium chloride, is completely ionized: Na. Cl(s) + H 2 O(l) 0. 10 M 0. 00 M Na. Cl(aq) Na +(aq) + Cl -(aq) 0. 10 M

Molarity (M) = Moles solute / Liter solution Electrolytes Concentrations: ð Ca. Cl 2

Molarity (M) = Moles solute / Liter solution Electrolytes Concentrations: ð Ca. Cl 2 (s) + H 2 O(l) Ca. Cl 2(aq) 0. 10 M Ca 2+(aq) + 2 Cl -(aq) 0. 00 M 0. 10 M 0. 20 M ð

Molarity (M) = Moles solute / Liter solution Electrolytes Sugars like sucrose are non-ionic,

Molarity (M) = Moles solute / Liter solution Electrolytes Sugars like sucrose are non-ionic, molecular compounds that dissolve but produce no ions. C 12 H 22 O 11 (S) + H 2 O(l) C 12 H 22 O 11 (aq) Some molecular compounds like acetic acid ionize partially (dissociate) in water HC 2 H 3 O 2 (l) + H 2 O(l) 0. 1000 M 0. 9987 M H 3 O+(aq)+ C 2 H 3 O 2 -(aq) 0. 0013 M

Aqueous Acids ð Any compound that provides a proton can be considered an acid.

Aqueous Acids ð Any compound that provides a proton can be considered an acid. Strong acids are sulfuric acid, nitric acid, perchloric acid, HI, HBr and HCl.

Electrolytes ð How would the conductivity of acetic acid compare to hydrochloric acid?

Electrolytes ð How would the conductivity of acetic acid compare to hydrochloric acid?

HCl Completely Ionized Acetic Acid (HC 2 H 3 O 2)

HCl Completely Ionized Acetic Acid (HC 2 H 3 O 2)

Aqueous Bases Any compound that accepts a proton is a base. The common bases

Aqueous Bases Any compound that accepts a proton is a base. The common bases are group IA & IIA metal hydroxide compounds. They are strong bases, dissociating completely in water. An example of a weak base is ammonia. NH 3 (g) + H 2 O(l) NH 3 (aq) NH 4+(aq)+ OH-(aq) Consider that aqueous ammonia is in equilibrium with ammonium hydroxide. The names have often been used interchangeably.

An Aqueous Solution of Sodium Hydroxide NH 3 in Water

An Aqueous Solution of Sodium Hydroxide NH 3 in Water

QUESTION

QUESTION

ANSWER

ANSWER

Aqueous Reactions: Neutralization

Aqueous Reactions: Neutralization

Aqueous Reactions: Neutralization Net Ionic Equations HCl(aq) + Na. OH (aq) __________________________ Na. Cl

Aqueous Reactions: Neutralization Net Ionic Equations HCl(aq) + Na. OH (aq) __________________________ Na. Cl (aq) + H 2 O(l) HCl(aq) H+(aq) + Cl -(aq) ð Na. OH (aq) Na+(aq)+ OH-(aq) ð Na. Cl (aq) Na+(aq)+ Cl-(aq) ð ________________________ Na+(aq)+ OH-(aq) + H+(aq) + Cl -(aq) Na+(aq)+ Cl-(aq) + H 2 O(l) ____________________________ H+(aq) + OH -(aq) H 2 O(l)

QUESTION An aqueous solution of H 2 SO 4 is added to aqueous Ba(OH)2.

QUESTION An aqueous solution of H 2 SO 4 is added to aqueous Ba(OH)2. The reaction is monitored using a conductivity tester. Predict the correct statement(s). I) Both H 2 SO 4 and Ba(OH)2 are strong electrolytes. II) This is a neutralization reaction. III) This is a precipitation reaction. IV) The light bulb will glow at the neutralization point. A) II B) I and II C) I, II and III D) I, III and IV

ANSWER An aqueous solution of H 2 SO 4 is added to aqueous Ba(OH)2.

ANSWER An aqueous solution of H 2 SO 4 is added to aqueous Ba(OH)2. The reaction is monitored using a conductivity tester. Predict the correct statement(s). I) Both H 2 SO 4 and Ba(OH)2 are strong electrolytes. II) This is a neutralization reaction. III) This is a precipitation reaction. IV) The light bulb will glow at the neutralization point. A) II B) I and II C) I, II and III D) I, III and IV

Aqueous Reactions: Acid-Base

Aqueous Reactions: Acid-Base

QUESTION If an antacid contains Al(OH)3 it will form Al. Cl 3 upon neutralization

QUESTION If an antacid contains Al(OH)3 it will form Al. Cl 3 upon neutralization of stomach acid. How many moles of Cl– ions are in 100. 0 m. L of 0. 010 M Al. Cl 3? A. 0. 0010 M B. 0. 010 M C. 0. 0030 M D. 0. 030 M Molarity (M) = Moles solute / Liter solution

ANSWER If an antacid contains Al(OH)3 it will form Al. Cl 3 upon neutralization

ANSWER If an antacid contains Al(OH)3 it will form Al. Cl 3 upon neutralization of stomach acid. How many moles of Cl– ions are in 100. 0 m. L of 0. 010 M Al. Cl 3? A. 0. 0010 M B. 0. 010 M C. 0. 0030 M D. 0. 030 M Al. Cl 3 dissociates into 3 moles of Cl–. Molarity (M) = Moles solute / Liter solution

QUESTION

QUESTION

ANSWER

ANSWER

What type of reaction is it? Double Displacement & Precipitation Write a balanced equation

What type of reaction is it? Double Displacement & Precipitation Write a balanced equation for the reaction. Pb(NO 3)2 (aq) + 2 Na. I (aq) 2 Na. NO 3(aq) + Pb. I 2(s) How do you know the state of the products: (s) vs. (aq)?

QUESTION Given the insoluble compound Al 2(CO 3)3 predict the ions and coefficients that

QUESTION Given the insoluble compound Al 2(CO 3)3 predict the ions and coefficients that would be necessary to complete the following net ionic equation: __ _____ + _____ Al 2(CO 3)3 • 2 Al. Cl 3 + 3 Na 2 CO 3 also include 6 Na. Cl on right • 3 Al 3+ + 2 CO 32– • 2 Al 3+ + 3 CO 32– • 2 Al 3+ 6 Cl – + 3 CO 32– + 6 Na+

ANSWER Given the insoluble compound Al 2(CO 3)3 predict the ions and coefficients that

ANSWER Given the insoluble compound Al 2(CO 3)3 predict the ions and coefficients that would be necessary to complete the following net ionic equation: __ _____ + _____ Al 2(CO 3)3 • 2 Al. Cl 3 + 3 Na 2 CO 3 also include 6 Na. Cl on right • 3 Al 3+ + 2 CO 32– • 2 Al 3+ + 3 CO 32– • 2 Al 3+ 6 Cl – + 3 CO 32– + 6 Na+

Aqueous Reactions: Precipitation Net Ionic Equations 50 m. L of a 0. 1 M

Aqueous Reactions: Precipitation Net Ionic Equations 50 m. L of a 0. 1 M solution of sodium sulfate is mixed with 50 m. L of a 0. 2 M solution of silver nitrate. What is the result? Molecular Equation: ? Na 2 SO 4(aq)+ ? Ag. NO 3(aq) 1 2 1 ? Ag 2 SO 4(s) + ? Na. NO 3(aq) 2

Aqueous Reactions: Precipitation Net Ionic Equations Na 2 SO 4(aq)+ 2 Ag. NO 3(aq)

Aqueous Reactions: Precipitation Net Ionic Equations Na 2 SO 4(aq)+ 2 Ag. NO 3(aq) Ag 2 SO 4(s)+ 2 Na. NO 3(aq) 0. 1 M 0. 2 M Ionic Reaction (Reactants): Na 2 SO 4(aq) 2 Ag. NO 3(aq) 2 Na+(aq) + SO 42 -(aq) 2 Ag+(aq) + 2 NO 31 -(aq) 2 Na+(aq)+ SO 42 -(aq)+ 2 Ag+(aq)+ 2 NO 31 -(aq) 0. 2 M 0. 1 M 0. 2 M

Aqueous Reactions: Precipitation Net Ionic Equations Na 2 SO 4(aq)+ 2 Ag. NO 3(aq)

Aqueous Reactions: Precipitation Net Ionic Equations Na 2 SO 4(aq)+ 2 Ag. NO 3(aq) Ag 2 SO 4(s)+ 2 Na. NO 3(aq) 0. 1 M 0. 2 M Ionic Reaction (Products): 2 Na. NO 3(aq) 2 Na+(aq) + 2 NO 31 -(aq) Ag 2 SO 4(s) Does not dissolve (ionize) 2 Na+(aq)+ 2 NO 31 -(aq) + Ag 2 SO 4(s) 0. 2 M solid

Aqueous Reactions: Precipitation Net Ionic Equations Na 2 SO 4(aq)+ 2 Ag. NO 3(aq)

Aqueous Reactions: Precipitation Net Ionic Equations Na 2 SO 4(aq)+ 2 Ag. NO 3(aq) Ag 2 SO 4(s)+ 2 Na. NO 3(aq) Overall Ionic Reaction: 2 Na+(aq)+ SO 42 -(aq) +2 Ag+(aq)+ 2 NO 31 -(aq) 2 Na+(aq) + Ag 2 SO 4(s) + 2 NO 31 -(aq) Net Ionic Equation: (Subtract Spectator Ions) 2 Ag+(aq)+ SO 42 -(aq) M x Vsolution= mol Ag 2 SO 4(s) How many moles? = MNa 2 SO 4 x. VNa 2 SO 4 / 1: 1 stoichiometry = 0. 10 M x 0. 050 L/ 1 = 0. 0050 mol

QUESTION

QUESTION

ANSWER –

ANSWER –

Pb(NO 3)2 (aq) + 2 Na. I (aq) 2 Na. NO 3(aq) + Pb.

Pb(NO 3)2 (aq) + 2 Na. I (aq) 2 Na. NO 3(aq) + Pb. I 2(s) Write a balanced Net Ionic equation for the reaction. Pb 2+ (aq) + 2 I 1 - (aq) Pb. I 2(s) What are the spectator ions in the reaction? 2 Na 1+ (aq); 2 NO 31 - (aq)

QUESTION

QUESTION

ANSWER E) All of these are soluble in water. According to the solubility rules

ANSWER E) All of these are soluble in water. According to the solubility rules for ionic compounds, compounds containing Group IA ions or nitrate ions will always be soluble. Compounds containing halides are generally soluble, aside from silver, lead and mercury(I) halides.

QUESTION If you began a reaction with the following ions in solution (all would

QUESTION If you began a reaction with the following ions in solution (all would be written with an (aq) subscript how would you represent the proper final net ionic equation? (Consult a solubility Table. ) 6 Na+ + 2 PO 43– + 3 Fe 2+ + 6 NO 3– • • 3 Na+ + PO 43– + Fe 2+ + 2 NO 3– No Reaction 6 Na+ + 2 PO 43– + 3 Fe 2+ + 6 NO 3– Fe 3(PO 4)2 (s)+ 6 Na. NO 3 3 Na+ + PO 43– + Fe 2+ + 2 NO 3– Fe 3(PO 4)2 (s)+ 6 Na+ + 6 NO 3– 2 PO 43– + 3 Fe 2+ Fe 3(PO 4)2 (s)

ANSWER If you began a reaction with the following ions in solution (all would

ANSWER If you began a reaction with the following ions in solution (all would be written with an (aq) subscript how would you represent the proper final net ionic equation? (Consult a solubility Table. ) 6 Na+ + 2 PO 43– + 3 Fe 2+ + 6 NO 3– • • 3 Na+ + PO 43– + Fe 2+ + 2 NO 3– No Reaction 6 Na+ + 2 PO 43– + 3 Fe 2+ + 6 NO 3– Fe 3(PO 4)2 (s)+ 6 Na. NO 3 3 Na+ + PO 43– + Fe 2+ + 2 NO 3– Fe 3(PO 4)2 (s)+ 6 Na+ + 6 NO 3– 2 PO 43– + 3 Fe 2+ Fe 3(PO 4)2 (s)

Oxidation-Reduction ð Oxidation is the loss of electrons. ð Reduction is the gain of

Oxidation-Reduction ð Oxidation is the loss of electrons. ð Reduction is the gain of electrons. ð The reactions occur together. One does not occur without the other. ð The terms are used relative to the change in the oxidation state or oxidation number of the reactant(s).

Aqueous Reactions: Oxidation - Reduction ð In the following reaction, identify what is being

Aqueous Reactions: Oxidation - Reduction ð In the following reaction, identify what is being oxidized and what is being reduced. What is the total number of electrons involved in the process?

Oxidation Reduction Reactions

Oxidation Reduction Reactions

QUESTION In a redox reaction, oxidation and reduction must both occur. Which statement provides

QUESTION In a redox reaction, oxidation and reduction must both occur. Which statement provides an accurate premise of redox chemistry? A. The substance that is oxidized must be the oxidizing agent. B. The substance that is oxidized must gain electrons. C. The substance that is oxidized must have a higher oxidation number afterwards. D. The substance that is oxidized must combine with oxygen.

ANSWER In a redox reaction, oxidation and reduction must both occur. Which statement provides

ANSWER In a redox reaction, oxidation and reduction must both occur. Which statement provides an accurate premise of redox chemistry? A. The substance that is oxidized must be the oxidizing agent. B. The substance that is oxidized must gain electrons. C. The substance that is oxidized must have a higher oxidation number afterwards. D. The substance that is oxidized must combine with oxygen.

QUESTION

QUESTION

ANSWER B) NO 2 Oxygen almost always has an oxidation state of – 2

ANSWER B) NO 2 Oxygen almost always has an oxidation state of – 2 when part of a compound. The exception is when it is part of a peroxide. For example, hydrogen peroxide H 2 O 2. Then it has an oxidation state of – 1.