AP PHYSICS Chapter 23 Problems Light Geometric Optics

AP PHYSICS Chapter 23 Problems Light: Geometric Optics

AP MIRROR PROBLEMS page 717 #1 and #4 mirror #1. 1. 5 m YOU 1. 5 m IMAGE 3 m

page 717 #4 mirror i 1. 62 m normal x 2. 10 m 43 cm

#4 cont'd 1. i = i at normal Geometry 2. 3. = r = i r at normal Physics r at base mirror i 1. 62 m i r x 2. 10 m r Normal 43 cm Geometry

#4 cont'd mirror i 1. tan 1. 62 m i r x 2. 10 m 1. 62 -. 43 1. 19 Normal 43 cm r i= i = 1. 19/2. 10 29. 54 i 2. 10 2. = r r = 29. 54 i . 43 r x tan 29. 54 =. 43/x x =. 76 m = 76 cm

1. A ray of light strikes a mirror at an angle of 530 to the normal. a) What is the angle of reflection? 530 b) What is the angle between the incident and reflected ray? 1060 inc d ide ref nt 530 te c le

2. A ray of light incident upon a mirror makes an angle of 360 with the mirror. What is the angle between the incident ray and the reflected ray? 1080 540 360

page 719 26 - 28 26. n = c/v crown glass 1. 52 = 3 x 10 8 / v v = 1. 97 x 10 8 m/s lucite 1. 51 = 3 x 10 8 / v v = 1. 99 x 10 8 m/s 27. nice = 3 x 10 8 / 2. 29 x 10 8 nice = 1. 31 28. nwater = 1. 33 = 3 x 10 8 / v v = 2. 26 x 10 8 m/s n = 3 x 10 8 / (. 85 v) n = 1. 56 n = 3 x 10 8 / (. 85*2. 26 x 108)

page 719 30 - 33 not drawn to scale normal i air n = 1. 0 30. n = 1. 0 r 31. glass r 1. 0 sin 63 = 1. 5 sin r= water n = 1. 5 i 1. 33 sin 42. 5 = 1. 0 sin 36. 44 normal air 32. = 63. 97 r normal n = 1. 0 r n = 1. 33 air i n = 1. 0 33. water i 1. 33 sin = 1. 0 sin 60 i= water n = 1. 33 40. 63 r 1. 0 sin i n = 1. 33 sin 21 =28. 47 to normal 90 - 28. 47 = 61. 53 to horizon

page 719 34 not drawn to scale 45 27. 72 air to prism 1. 0 sin 45 = 1. 52 sin r' r' = 27. 72 8 2 32. 54. 27 internal (90 -27. 72) + (90 - i' ) + 60 = 180 i' = 32. 28 prism to air 1. 52 sin 32. 28 = 1. 0 sin 54. 27 r = 54. 27

page 719 35 not drawn to scale a 1. 3 m i 2. 7 m 2. 1 m = 25. 71 i i = 90 - 25. 71 1. 3 a = 64. 29 2. Physics air to water 1. 0 sin 64. 29 = 1. 33 sin r = 42. 64 b 2. 7 m 1. Geometry tan = 1. 3/ 2. 7 r 2. 7 L 3. Geometry i tan 42. 64 = L / 2. 1 L = 1. 93 m 42. 64 2. 1 b L TOTAL LENGTH FROM EDGE 2. 7 + 1. 93 = 4. 63 m

page 719 36 not drawn to scale i Given: reflection i= Reflection= Therefore r air to glass Refraction i = 2 r = 2(40. 54) = 81. 08 1. 0 sin 2 r =1. 52 sin r* 2 sin r cos r = 1. 52 sin r 2 cos 2 * Trig sin 2 = 2 sin r = 1. 52 r =. 76 r = 40. 54 i = 2 r = 2(40. 54) = 81. 08 cos

FISH TANK Page 719 37 air not drawn to scale glass water n = 1. 52 n=1. 0 26. 93 normal 31. 17 26. 93 43. 5 1. air to glass 1. 0 sin 43. 5 = 1. 52 sin n = 1. 33 2. glass to water 1. 52 sin 26. 93 = 1. 33 sin r r =26. 93 r = 31. 17 If there was no glass air to water 1 sin 43. 5 = 1. 33 sin r = 31. 17 r r

sin page 719 40 - 44 40. Water n = 1. 33 sin =c 1. 33/1. 51 Lucite n = 1. 31 sin =c 1. 51/1. 33 The light must start in the lucite! 41. c = 44. 7 42. water to air sin c= 1/1. 33 liquid to air c = n 2/n 1 =c 61. 64 n 2/n 1 can not be greater than 1 sin 44. 7 = 1/n 1 = 1. 42 water air c= x 48. 75 tan 48. 75 = x / 62 62 cm x = 70. 71 cm 48. 75 43. d = L sin 44. tan = 7/8 10 -4 = L sin 15 L = 3. 9 x 10 -4 m = 41. 2 sin c = n 2/n 1 7 sin 41. 2 = 1/n 1 = 1. 52 Liquid must have an index of refraction greater than or equal to 1. 52 8