Announcement 1 r Did you all receive homework

Announcement #1 r Did you all receive homework #1 and #2? r Homework #3 will be available online during the day r Midterm 1

Announcement #2 r CS 395/495 Advanced Networking r “Let’s bring down the Internet together!” r Classes m Analyzing some classical and novel networking papers • You read the paper and provide a review before the class • Two teams give opposite presentation in-favor and against the paper (20 minutes each) • Two teams argue about the paper (20 minutes) • The whole class discusses the paper (20 minutes) 2

CS 395/495 Advanced Networking r Projects m I will provide you with initial suggestions m You are free to come up with your own idea for the project m We will submit the best paper to a conference r Goals m To help you learn how to do networking (or more broadly systems) research m To help you learn how to argue and convey your ideas 3

Network Layer r Introduction r Virtual circuit and datagram networks r Routing algorithms m Link state m Distance vector m Hierarchical routing 4

Network layer r transport segment from r r sending to receiving host on sending side encapsulates segments into datagrams on rcving side, delivers segments to transport layer network layer protocols in every host, router Router examines header fields in all IP datagrams passing through it application transport network data link physical network data link physical network data link physical application transport network data link physical 5

Key Network-Layer Functions r forwarding: move packets from router’s input to appropriate router output r routing: determine route taken by packets from source to dest. m Routing analogy: r routing: process of planning trip from source to dest r forwarding: process of getting through single interchange algorithms 6

Interplay between routing and forwarding routing algorithm local forwarding table header value output link 0100 0101 0111 1001 3 2 2 1 value in arriving packet’s header 0111 1 3 2 7

Network Layer r Introduction r Virtual circuit and datagram networks r Routing algorithms m Link state m Distance vector m Hierarchical routing 8

Network layer connection and connection-less service r Datagram network provides network-layer connectionless service r VC network provides network-layer connection service r Analogous to the transport-layer services, but: m Service: host-to-host m No choice: network provides one or the other m Implementation: in the core 9

Virtual circuits “source-to-dest path behaves much like telephone circuit” m m performance-wise network actions along source-to-dest path r call setup, teardown for each call before data can flow r each packet carries VC identifier (not destination host address) r every router on source-dest path maintains “state” for each passing connection r link, router resources (bandwidth, buffers) may be allocated to VC 10

VC implementation A VC consists of: 1. 2. 3. Path from source to destination VC numbers, one number for each link along path Entries in forwarding tables in routers along path r Packet belonging to VC carries a VC number. r VC number must be changed on each link. m New VC number comes from forwarding table 11

Forwarding table VC number 22 12 1 Forwarding table in northwest router: Incoming interface 1 2 3 1 … 2 32 3 interface number Incoming VC # 12 63 7 97 … Outgoing interface 3 1 2 3 … Outgoing VC # 22 18 17 87 … Routers maintain connection state information! 12

Virtual circuits: signaling protocols r used to setup, maintain teardown VC r used in ATM, frame-relay, X. 25 r not used in today’s Internet application transport 5. Data flow begins network 4. Call connected data link 1. Initiate call physical 6. Receive data application 3. Accept call transport 2. incoming call network data link physical 13

Datagram networks r no call setup at network layer r routers: no state about end-to-end connections m no network-level concept of “connection” r packets forwarded using destination host address m packets between same source-dest pair may take different paths application transport network data link 1. Send data physical application transport 2. Receive data network data link physical 14

Datagram vs. VC r Which of the above introduces larger signaling load? m VC • each time a new connection arrives – a new VC has to be set • Each time a connection is closed – the state has to be changed in each router along the path m Datagram • No changes in routing tables are made because of flow arrivals/departures • Changes are made on much longer time-scales (e. g. , hours, days) 15

Forwarding table Destination Address Range 4 billion possible entries Link Interface 11001000 00010111 00010000 through 11001000 00010111 1111 0 11001000 00010111 00011000 0000 through 11001000 00010111 00011000 1111 1 11001000 00010111 00011001 0000 through 11001000 00010111 00011111 2 otherwise 3 16

Longest prefix matching Prefix Match 11001000 00010111 00010 11001000 00010111 00011000 11001000 00010111 00011 otherwise Link Interface 0 1 2 3 Examples DA: 11001000 00010111 00010110 10100001 Which interface? DA: 11001000 00010111 00011000 1010 Which interface? 17

Datagram or VC network: why? Internet r data exchange among ATM r evolved from telephony computers r human conversation: m “elastic” service, no strict m strict timing, reliability timing requirements r “smart” end systems m need for guaranteed (computers) service m can adapt, perform r “dumb” end systems control, error recovery m telephones m simple inside network, m complexity inside complexity at “edge” network r many link types m different characteristics m uniform service difficult 18

Network Layer r Introduction r Virtual circuit and datagram networks r Routing algorithms m Link state m Distance vector m Hierarchical routing 19

Interplay between routing and forwarding routing algorithm local forwarding table header value output link 0100 0101 0111 1001 3 2 2 1 value in arriving packet’s header 0111 1 3 2 20

Graph abstraction 5 2 u 2 1 Graph: G = (N, E) v x 3 w 3 1 5 z 1 y 2 N = set of routers = { u, v, w, x, y, z } E = set of links ={ (u, v), (u, x), (v, w), (x, y), (w, z), (y, z) } Remark: Graph abstraction is useful in other network contexts Example: P 2 P, where N is set of peers and E is set of TCP connections 21

Graph abstraction: costs 5 2 u v 2 1 x • c(x, x’) = cost of link (x, x’) 3 w 3 1 5 z 1 y - e. g. , c(w, z) = 5 2 • cost could always be 1, or inversely related to bandwidth, or inversely related to congestion Cost of path (x 1, x 2, x 3, …, xp) = c(x 1, x 2) + c(x 2, x 3) + … + c(xp-1, xp) Question: What’s the least-cost path between u and z ? Routing algorithm: algorithm that finds least-cost path 22

Routing Algorithm classification Global or decentralized information? Global: r all routers have complete topology, link cost info r “link state” algorithms Decentralized: r router knows physicallyconnected neighbors, link costs to neighbors r iterative process of computation, exchange of info with neighbors r “distance vector” algorithms Static or dynamic? Static: r routes change slowly over time Dynamic: r routes change more quickly m periodic update m in response to link cost changes 23

Network Layer r Introduction r Virtual circuit and datagram networks r Routing algorithms m Link state m Distance vector m Hierarchical routing 24

A Link-State Routing Algorithm Dijkstra’s algorithm r net topology, link costs known to all nodes m accomplished via “link state broadcast” m all nodes have same info r computes least cost paths from one node (‘source”) to all other nodes m gives forwarding table for that node r iterative: after k iterations, know least cost path to k dest. ’s Notation: r c(x, y): link cost from node x to y; = ∞ if not direct neighbors r D(v): current value of cost of path from source to dest. v r p(v): predecessor node along path from source to v r N': set of nodes whose least cost path definitively known 25

Dijsktra’s Algorithm 1 Initialization: 2 N' = {u} 3 for all nodes v 4 if v adjacent to u 5 then D(v) = c(u, v) 6 else D(v) = ∞ 7 8 Loop 9 find w not in N' such that D(w) is a minimum 10 add w to N' 11 update D(v) for all v adjacent to w and not in N' : 12 D(v) = min( D(v), D(w) + c(w, v) ) 13 /* new cost to v is either old cost to v or known 14 shortest path cost to w plus cost from w to v */ 15 until all nodes in N' 26

Dijkstra’s algorithm: example Step 0 1 2 3 4 5 N' u ux uxyvwz D(v), p(v) D(w), p(w) 2, u 5, u 2, u 4, x 2, u 3, y D(x), p(x) 1, u D(y), p(y) ∞ 2, x D(z), p(z) ∞ ∞ 4, y 5 2 u v 2 1 x 3 w 3 1 5 z 1 y 2 27

Dijkstra’s algorithm, discussion Algorithm complexity: n nodes r each iteration: need to check all nodes, w, not in N r n(n-1)/2 comparisons: O(n 2) r more efficient implementations possible: O(nlogn) Oscillations possible: r e. g. , link cost = amount of carried traffic D 1 1 0 A 0 0 C e 1+e e initially B 1 2+e A 0 D 1+e 1 B 0 0 C … recompute routing 0 D 1 A 0 0 C 2+e B 1+e … recompute 2+e A 0 D 1+e 1 B e 0 C … recompute 28