Advanced Chemistry Bell Ringers Semester 2 2015 Bell

Advanced Chemistry Bell Ringers Semester 2 2015

Bell Ringer Match the following conversions to their equivalents: 0. 357 atm 6. 6 x 10 -2 torr 1104 torr 271 torr 147. 2 k. Pa 8. 7 x 10 -5 atm

Bell Ringer Continued Match the following conversions to their equivalents: 0. 357 atm 6. 6 x 10 -2 torr 1104 torr 271 torr 147. 2 k. Pa 8. 7 x 10 -5 atm

Bell Ringer This chapter is governed by Boyle’s Law, Avagadro’s Law, Charle’s Law, and the Ideal Gas Law. Write a minimum of 11 sentences comparing and contrasting these laws and their relationships.

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What would a plot of P versus 1/V look like for a fixed quantity of gas at a fixed temperature? A. B. C. D. Polynomial curve of third order Quadratic Exponential Linear

Bell Ringer How many moles of gas are in each vessel? A. B. C. D. 0. 5 1 1. 5 2

Bell Ringer Your book states that the density of carbon dioxide vapor at 720 tor and 125 degrees Celsius is found to be 1. 276 g/L. Do you agree of disagree with the book’s answer key? Why or Why Not?

Bell Ringer Continued 720 torr(1 atm/760 torr) = 0. 947 atm MM of CO 2 is 44. 009 g/mol 125 degrees C + 273 = 398 K D = (0. 947 atm)(44. 009 g/mol) = 1. 3 g/L (0. 08206 L-atm/mol-K)(398 K) See Equation 10. 10 formula Don’t forget Sig Figs!

Bell Ringer A. B. C. D. Increasing P Increase Decrease Increase No change Increasing T Increase No change Decrease

Bell Ringer An inflated balloon has a volume of 6. 0 L at sea level (1. 0 atm) and is allowed to ascend until the pressure is 0. 45 atm. During ascent, the temperature of the gas falls from 22 C to 21 C. Calculate the volume of the balloon at its final altitude.

Bell Ringer Calculating the Effect of Changing P and T on Gas Volume An inflated balloon has a volume of 6. 0 L at sea level (1. 0 atm) and is allowed to ascend until the pressure is 0. 45 atm. During ascent, the temperature of the gas falls from 22 C to 21 C. Calculate the volume of the balloon at its final altitude. Because n is constant, we can use Equation 10. 8. Rearranging Equation 10. 8 to solve for V 2 gives

Bell Ringer In which of these substances is hydrogen bonding likely to play an important role in determining physical properties: methane (CH 4), hydrazine (H 2 NNH 2), methyl fluoride (CH 3 F), hydrogen sulfide (H 2 S)?

Bell Ringer In which of these substances is hydrogen bonding likely to play an important role in determining physical properties: methane (CH 4), hydrazine (H 2 NNH 2), methyl fluoride (CH 3 F), hydrogen sulfide (H 2 S)? We are given the chemical formulas of four compounds and asked to predict whether they can participate in hydrogen bonding. All the compounds contain H, but hydrogen bonding usually occurs only when the hydrogen is covalently bonded to N, O, or F. We analyze each formula to see if it contains N, O, or F directly bonded to H. There also needs to be a nonbonding pair of electrons on an electronegative atom (usually N, O, or F) in a nearby molecule, which can be revealed by drawing the Lewis structure for the molecule. The foregoing criteria eliminate CH 4 and H 2 S, which do not contain H bonded to N, O, or F. They also eliminate CH 3 F, whose Lewis structure shows a central C atom surrounded by three H atoms and an F atom. (Carbon always forms four bonds, whereas hydrogen and fluorine form one each. ) Because the molecule contains a C F bond and not a H F bond, it does not form hydrogen bonds. In H 2 NNH 2, however, we find N H bonds, and the Lewis structure shows a nonbonding pair of electrons on each N atom, telling us hydrogen bonds can exist between the molecules:

Bell Ringer Rank the substances Ba. Cl 2, H 2, CO, HF, and Ne in order of increasing boiling point.

Bell Ringer List the substances Ba. Cl 2, H 2, CO, HF, and Ne in order of increasing boiling point. We need to assess the intermolecular forces in these substances and use that information to determine the relative boiling points. The boiling point depends in part on the attractive forces in each substance. We need to order these according to the relative strengths of the different kinds of intermolecular attractions. The attractive forces are stronger for ionic substances than for molecular ones, so Ba. Cl 2 should have the highest boiling point. The intermolecular forces of the remaining substances depend on molecular weight, polarity, and hydrogen bonding. The molecular weights are H 2 (2), CO (28), HF (20), and Ne (20). The boiling point of H 2 should be the lowest because it is nonpolar and has the lowest molecular weight. The molecular weights of CO, HF, and Ne are similar. Because HF can hydrogen bond, however, it should have the highest boiling point of the three. Next is CO, which is slightly polar and has the highest molecular weight. Finally, Ne, which is nonpolar, should have the lowest boiling point of these three. The predicted order of boiling points is, therefore, H 2 < Ne < CO < HF < Ba. Cl 2

Bell Ringer Calculate the enthalpy change upon converting 1. 00 mol of ice at 25 C to steam at 125 C under a constant pressure of 1 atm. The specific heats of ice, liquid water, and steam are 2. 03 J/g-K, 4. 18 J/g-K, and 1. 84 J/g-K, respectively. For H 2 O, Hfus = 6. 01 k. J/mol and Hvap = 40. 67 k. J/mol.

Bell Ringer Calculate the enthalpy change upon converting 1. 00 mol of ice at 25 C to steam at 125 C under a constant pressure of 1 atm. The specific heats of ice, liquid water, and steam are 2. 03 J/g-K, 4. 18 J/g-K, and 1. 84 J/g-K, respectively. For H 2 O, Hfus = 6. 01 k. J/mol and Hvap = 40. 67 k. J/mol. Our goal is to calculate the total heat required to convert 1 mol of ice at 25 C to steam at 125 C. We can calculate the enthalpy change for each segment and then sum them to get the total enthalpy change (Hess’s law). For segment AB, we are adding enough heat to ice to increase its temperature by 25 C. A temperature change of 25 C is the same as a temperature change of 25 K, so we can use the specific heat of ice to calculate the enthalpy change during this process: AB: H = (1. 00 mol)(18. 0 g/mol)(2. 03 J/g-K)(25 K) = 914 J = 0. 91 k. J

Bell Ringer Continued… For segment BC, in which we convert ice to water at 0 C, we can use the molar enthalpy of fusion directly: The enthalpy changes for segments CD, DE, and EF can be calculated in similar fashion: The total enthalpy change is the sum of the changes of the individual steps: BC: H = (1. 00 mol)(6. 01 k. J/mol) = 6. 01 k. J CD: H = (1. 00 mol)(18. 0 g/mol)(4. 18 J/g-K)(100 K) = 7520 J = 7. 52 k. J DE: H = (1. 00 mol)(40. 67 k. J/mol) = 40. 7 k. J EF: H = (1. 00 mol)(18. 0 g/mol)(1. 84 J/g-K)(25 K) = 830 J = 0. 83 k. J H = 0. 91 k. J + 6. 01 k. J + 7. 52 k. J + 40. 7 k. J + 0. 83 k. J = 56. 0 k. J

Bell Ringer Day 1 of 4 for our Final Cation Lab You will use a hand out to begin writing up our Lab Log entry. I. Procedures…detailed by simplified (should have prediction prior to starting) II. Safety-MSDS is a good resource III. Data/Observation Table ready for collection IN PEN…Partners are fine to this point

Lab Day 2 of 4 Data Collection Before you can begin collecting data…you must have your lab book entry preapproved. I. Procedures-short and sweet but shouldn’t need the manual to know how to do the lab. WITH A Prediction! II. Safety section for chemicals and equipment we are using. MSDS is your BFF. III. Data/Observations (begin after approval)

Lab Day 3 of 4 Unknown Day! May the force be with you and not the m x a kind… Remember a full lab report includes: Intro, Procedures, Safety, Data & Observations, Calculations & Results (excel graphs etc), Discussion of Results, References in ACS and Additional Questions. You will be submitting all 8 sections to the turnitin. com account. No 3 rd Person! Individual work!

Lab Day 4 of 4 Remember a full lab report includes: Intro, Procedures, Safety, Data & Observations, Calculations & Results (excel graphs etc), Discussion of Results, References in ACS and Additional Questions. You will be submitting all 8 sections to the turnitin. com account. No 3 rd Person! Individual work!

Bell Ringer Break down the roots of what dynamic equilibrium means and explain how butanol will reach dynamic equilibrium more quickly then dihydrogen monoxide.

Bell Ringer Chapter 11 Quiz Today… Please have your remotes, scratch paper if you choose, Periodic Table and calculator ready!

Chapters 10 & 11 Exam Pick up your remote from the CPS bag. Be sure that it is YOUR number. Begin testing immediately. You may use: Scratch paper and a NONProgrammable Calculator. No Cell Phones!

Bell Ringer Which two thermodynamic quantities determine whether or not a process is spontaneous? A. B. C. D. Enthalpy and work Entropy and heat flow Entropy and enthalpy

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Bell Ringer Continued… How does the magnitude of ΔHmix compare with the magnitude of ΔHsolute + ΔHsolvent for exothermic solution processes? A. B. C. Larger Almost the same Smaller

Bell Ringer If an aqueous solution is very dilute, will its molality be greater than its molarity, nearly the same as it molarity, or smaller than its molarity? A. Molality will be greater than its molarity. B. Molality will be nearly the same as its molarity. C. Molality will be smaller than its molarity.

How does the solubility of KCl at 80° C compare with that of Na. Cl at the same temperature? A. Na. Cl is more soluble. B. KCl is more soluble. C. Na. Cl and KCl have about the same solubility.

Bell Ringer Today is your Exam II over chapters 11. 4+ and Chapter 13… Please have your remote, paper for showing your work and non-programmable calculator ready.

Bell Ringer Calculating an Average Rate of Reaction From the data in Figure 14. 3, calculate the average rate at which A disappears over the time interval from 20 s to 40 s.

Bell Ringer Continued… We are given the concentration of A at 20 s (0. 54 M) and at 40 s (0. 30 M) and asked to calculate the average rate of reaction over this time interval. The average rate is given by the change in concentration, [A], divided by the change in time, t. Because A is a reactant, a minus sign is used in the calculation to make the rate a positive quantity.

Bell Ringer How do reaction rate, rate constant, and rate law differ? (1) (2) (3) (4) (5) A. B. C. D. Reaction rate is experimentally measured as a reaction proceeds. Rate constant is calculated from a rate law. Rate law relates reaction rate to rate constant and concentrations. Rate law describes the mechanism of a reaction. Reaction rate depends on the stoichiometry of the reaction. (1), (2), (4), (4) (2), (3), (5) (1), (2), (3)

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How does the energy needed to overcome the energy barrier compare with the overall change in energy for this reaction? A. B. C. D. Similar in magnitude Extremely different in magnitude About twice as large as overall change in energy About half as large as the overall change in energy

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Where are the intermediates and transition states in this diagram? Red curve A. peak B. C. D. Blue curve Top of peak; no intermediates top of first peak; top of second Top of peak; top of peakboth in the “valley” between peaks Top of peak; top of peaktop of both peaks; no intermediates Top of peak; no intermediates top of both peaks; in the “valley” between the peaks

Bell Ringer (a) A. B. C. D. 2 nd order in NO, 1 st order in H 2, 2 nd order overall 2 nd order in NO, 1 st order in H 2, 3 rd order overall 1 st order in NO, 1 st order in H 2, 2 nd order overall 1 st order in NO, 2 nd order in H 2, 3 rd order overall

Bell Ringer Writing Equilibrium-Constant Expressions Write the equilibrium expression for Kc for the following reactions: (a) (b) (c)

Bell Ringer We are given three equations and are asked to write an equilibrium-constant expression for each. Using the law of mass action, we write each expression as a quotient having the product concentration terms in the numerator and the reactant concentration terms in the denominator. Each concentration term is raised to the power of its coefficient in the balanced chemical equation. (a) (b) (c)

Bell Ringer (a) A. B. C. D. Moles of reactant always equals moles of product. Mass of reactant always equals mass of product. The rates of opposing reactions are equal. Cannot be determined without temperature information

Bell Ringer Continued… (b) A. B. C. D. The constant will be greater than 1. The constant will be less than 1. The constant will be equal to zero. Cannot determine without temperature information

Bell Ringer A. Kc represents the equilibrium constant when equilibrium (equil. ) concentrations (conc. ) are expressed in molarity and Kp represents the equil. constant when equil. conc. are expressed in atm. B. Kc and Kp are the rate constants expressed in M/time and atm/time respectively. C. Kc and Kp are the equil. constants with units of molarity and atmospheres, respectively. D. Kc and Kp are the rate constants used to determine rates of solution and gaseous reactions respectively.

Bell Ringer Converting between Kc and Kp For the Haber process, Kc = 9. 60 at 300 C. Calculate Kp for this reaction at this temperature.

Bell Ringer We are given Kc for a reaction and asked to calculate Kp. The relationship between Kc and Kp is given by Equation 15. 14. To apply that equation, we must determine n by comparing the number of moles of product with the number of moles of reactants (Equation 15. 15). With 2 mol of gaseous products (2 NH 3) and 4 mol of gaseous reactants, (1 N 2 + 3 H 2), n = 2 – 4 =2. (Remember that functions are always based on products minus reactants. ) The temperature is 273 + 300 = 573 K. The value for the idealgas constant, R, is 0. 08206 L-atm/mol-K. Using Kc = 9. 60, we therefore have

Bell Ringer A. B. C. D. The equilibrium shifts to the left. The equilibrium does not change. The equilibrium shifts to the right. Cannot determine what happens without knowing the magnitude of increase in volume

Bell Ringer Day 1 of 4 for our Lab You will use a hand out to begin writing up our Lab Log entry. I. Procedures…detailed by simplified (should have prediction prior to starting) II. Safety-MSDS is a good resource III. Data/Observation Table ready for collection IN PEN…Partners are fine to this point

Lab Day 2 of 4 Data Collection Before you can begin collecting data…you must have your lab book entry preapproved. I. Procedures-short and sweet but shouldn’t need the manual to know how to do the lab. WITH A Prediction! II. Safety section for chemicals and equipment we are using. MSDS is your BFF. III. Data/Observations (begin after approval)

Lab Day 3 of 4 Unknown Day! May the force be with you and not the m x a kind… Remember a full lab report includes: Intro, Procedures, Safety, Data & Observations, Calculations & Results (excel graphs etc), Discussion of Results, References in ACS and Additional Questions. You will be submitting all 8 sections to the turnitin. com account. No 3 rd Person! Individual work!

Lab Day 4 of 4 Remember a full lab report includes: Intro, Procedures, Safety, Data & Observations, Calculations & Results (excel graphs etc), Discussion of Results, References in ACS and Additional Questions. You will be submitting all 8 sections to the turnitin. com account. No 3 rd Person! Individual work!

Chapters 14 & 15 Exam III Pick up your remote from the CPS bag. Be sure that it is YOUR number. Begin testing immediately. You may use: Paper to show your work and a NON-Programmable Calculator. No Cell Phones!

Bell Ringer Day 1 of 3 for our Lab You will use a hand out to begin writing up our Lab Log entry. I. Procedures…detailed by simplified (should have prediction prior to starting) II. Safety-MSDS is a good resource III. Data/Observation Table ready for collection IN PEN…Partners are fine to this point

Lab Day 2 of 3 Data Collection Before you can begin collecting data…you must have your lab book entry preapproved. I. Procedures-short and sweet but shouldn’t need the manual to know how to do the lab. WITH A Prediction! II. Safety section for chemicals and equipment we are using. MSDS is your BFF. III. Data/Observations (begin after approval)

Lab Day 3 of 3 Final Day for Calcium Data Collection! Remember a full lab report includes: Intro, Procedures, Safety, Data & Observations, Calculations & Results (excel graphs etc), Discussion of Results, References in ACS and Additional Questions. You will be submitting all 8 sections to me on Tuesday after the break. Paper copy submission please… No 3 rd Person! Individual work!

Bell Ringer The Ka formic acid (HCHO 2) is 1. 8 ˛ 10 -4. What is the p. H of a 0. 35 -M aqueous solution of sodium formate (Na. CHO 2)? A) 5. 36 B) B) 8. 64 C) C) 10. 71 D) D) 4. 20 E) E) 3. 29

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Bell Ringer Compare and contrast Arrhenius & BL acid and base definitions. Be prepared to share: 1 -thing they have in common 2 -things they have different 3 -concept you remember from the past with acids and bases (can be any random fact)

Bell Ringer If the p. OH for a solution is 3. 00, what is the p. H? Is the solution acidic or basic? A. B. C. D. p. H = 17. 00; basic because p. H > 7 p. H = 11. 00; basic because p. H > 7 p. H = 3. 00; acidic because p. H < 7 The p. H cannot be determined without [H+] information. Solution is basic because p. OH < 7.

Bell Ringer Why can we generally assume that the equilibrium concentration of a weak acid equals its initial concentration? A. B. C. D Because Ka for weak acids slightly less than 1 and therefore, the extent of ionization is very small and can be neglected. Because most weak acids of low to moderate concentration undergo very little ionization, often less than 1% in solution, and thus the extent of ionization can be neglected. Because most weak acids of high or low concentration will form minimal conjugate base and thus the extent of ionization can be neglected. Because for each weak acid dissociating in solution, a weak acid molecule is formed with minimal conjugate base forming and thus the extent of ionization can be neglected.

Bell Ringer What is the p. Ka value for HF? What is the p. Kb value for F-? p. Ka(HF) A. 3. 17 B. 10. 83 C. 9. 60 D. 4. 40 p. Kb(F–) 10. 83 3. 17 4. 40 9. 60

Bell Ringer Turn to page 691 of our book. Note the Sample Integrated Exercise. This example is AWESOME! Please take 3 minutes to copy this example into your learning log to be used on your quiz today. I will take 3 questions or comments when you are finished about this example before we begin our quiz.

Bell Ringer Today is a Exam 4 Work Day! Please find 2 questions from our Socrative you are not confident in. Be prepared to share those questions with your peers.

Exam IV Pick up your remote from the CPS bag. Be sure that it is YOUR number. Begin testing immediately. You may use: Paper to show your work and a calculator. No Cell Phones!

Bell Ringer Balance the following reaction: Zn + H 2 SO 4 Zn. SO 4 + H 2 Mg + O 2 Mg. O Ca. C 2 + H 2 O Ca(OH)2 + C 2 H 2 (CH 3)2 CHOH + O 2 H 2 O + CO 2 Cu. SO 4 5 H 2 O Cu. SO 4 + H 2 O

Bell Ringer Your sample contains 50 ml of. 1 M HCl. What volume of Na. OH(aq) would be needed to reach the equivalence point if the concentration if the added base were 0. 200 M?

Bell Ringer A. HCl. O because it is a stronger weak acid. A salt containing Cl. O– is also needed. B. HNO 2 because it is a stronger weak acid. A salt containing NO 2– is also needed. C. HCl. O because its p. Ka is closer to p. H = 7. 0. A salt containing Cl. O– is also needed. D. HNO 2 because its p. Ka is closer to p. H = 7. 0. A salt containing NO 2– is also needed.

Bell Ringer A. B. C. D. p. H = 4. 2 p. H = 7. 0 p. H = 8. 2 p. H = 9. 8

Bell Ringer A. B. C. D. The nearly vertical equivalence point portion of the titration curve is large for a weak acid-strong base titration, and fewer indicators undergo their color change so quickly because the change is difficult to monitor. The nearly vertical equivalence point portion of the titration curve is smaller for a weak acid-strong base titration, and fewer indicators undergo their color change within this narrow range. Many indicators do not change colors at the equivalence points of weak acid-strong base titrations. Equivalence points at p. H’s other than 7. 00 are difficult to determine.

Bell Ringer What is the number one greenhouse gas in the Earth’ atmosphere?

A. Amphoteric substances are acids whereas amphiprotic substances are acids. B. Amphoteric substances are bases whereas amphiprotic substances are acids. C. Amphoteric substances can act both as an acid and a base whereas amphiprotic substances are acids. D. Amphoteric substances can act both as an acid and a base whereas amphiprotic substances can accept or donate a proton.

Exam V Pick up your remote from the CPS bag. Be sure that it is YOUR number. Begin testing immediately. P. S. Last Book Exam Until the Final!!! You may use: Paper to show your work and a NON-Programmable Calculator. No Cell Phones!

Bell Ringer Day 1 of 4 for our Lab You will use a hand out to begin writing up our Lab Log entry. I. Procedures…detailed by simplified (should have prediction prior to starting) II. Safety-MSDS is a good resource III. Data/Observation Table ready for collection IN PEN…Partners are fine to this point

Lab Day 2 of 4 Data Collection Before you can begin collecting data…you must have your lab book entry preapproved. I. Procedures-short and sweet but shouldn’t need the manual to know how to do the lab. WITH A Prediction! II. Safety section for chemicals and equipment we are using. MSDS is your BFF. III. Data/Observations (begin after approval)

Lab Day 3 of 4 Final Day for Calcium Data Collection! Remember a full lab report includes: Intro, Procedures, Safety, Data & Observations, Calculations & Results (excel graphs etc), Discussion of Results, References in ACS and Additional Questions. You will be submitting all 8 sections to me on Tuesday after the break. Paper copy submission please… No 3 rd Person! Individual work!

Lab Day 4 of 4 Final Day for Calcium Data Collection! Remember a full lab report includes: Intro, Procedures, Safety, Data & Observations, Calculations & Results (excel graphs etc), Discussion of Results, References in ACS and Additional Questions. You will be submitting all 8 sections to me on Tuesday after the break. Paper copy submission please… No 3 rd Person! Individual work!

Bell Ringer A. B. Yes. Nonspontaneous processes can never occur under any circumstances. Nonspontaneous processes can occur with some continuous external assistance.

Bell Ringer The value of S is a state function because q is constant for a specified T irrespective of the path chosen. B. S depends not merely on q but on qrev. There is only one reversible isothermal path between two states regardless of the number of possible paths. C. S has negligible dependence on q and thus q does not affect the state function properties of S or S. D. H = qp. H is directly related to q. H is a state function; thus, S is also a state function. A.

Bell Ringer A. We need to know if the change involves a closed or open system to make a conclusion. B. The entropy of the surroundings must increase by the same amount as the entropy decrease of the system. C. The entropy of the surroundings must increase by a greater amount than the entropy decrease of the system. D. The entropy of the surroundings must decrease by a smaller amount than the entropy decrease of the system.

Bell Ringer A. B. C. Always increase Always decrease Sometimes increases and sometimes decreases, depending on the process

Bell Ringer A. B. C. D. H = T S H < T S H > T S Cannot determine without additional information

Bell Ringer A. B. C. D. N, +1; N, +2; N, +3; N, +4; O, – 1 O, – 2

Bell Ringer A. Yes, in each half-reaction B. Yes, on both sides of the balanced equation for a redox reaction C. No, the electrons do not show in half-reactions and therefore they do not appear in a balanced equation for a redox reaction. D. No, the electrons cancel in adding half-reactions to form a balanced equation for a redox reaction.

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Explain (a) the vigorous bubbling in the beaker on the right and (b) the formation of steam above that beaker. A. (a) Bubbling is caused by water vapor escaping and (b) the exothermic reaction in water produces steam. B. (a) Bubbling is caused by water vapor escaping and (b) the endothermic reaction in water produces steam. C. (a) Bubbling is caused by hydrogen gas forming and (b) the endothermic reaction in water produces steam. D. (a) Bubbling is caused by hydrogen gas forming and (b) the exothermic reaction in water produces steam.

Bell Ringer Have your learning log out and be ready for 20. 1 and 20. 2 presentations.

Bell Ringer Have your learning log out and be ready for 20. 3 and 20. 4 presentations.

Bell Ringer Have your learning log out and be ready for 20. 5 and 20. 6 presentations.

Bell Ringer Have your learning log out and be ready for 20. 7, 20. 8 and 20. 9 presentations.

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Which species is reduced in this reaction? Which species is the reducing agent? A. B. C. D. Mn. O 4 - is reduced and the reducing agent is H+. Mn. O 4 - is reduced and the reducing agent is C 2 O 42 -. H+ is reduced and the reducing agent is Mn. O 4 -.

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Which metal, Cu or Zn, is oxidized in this voltaic cell? A. B. C. D. Cu, because it loses electrons in the chemical reaction. Cu, because it gains electrons in the chemical reaction. Zn, because it loses electrons in the chemical reaction. Zn, because it gains electrons in the chemical reaction.

Bell Ringer Pick up your lab drawer key and be ready to check in your materials.

Bell Ringer ACS Practice for the Final Day…No time to play. Be seated and ready for instructions. Today’s Topic: Dynamics

Bell Ringer ACS Practice for the Final Day…No time to play. Be seated and ready for instructions. Today’s Topic: Equilbrium

Bell Ringer ACS Practice for the Final Day…No time to play. Be seated and ready for instructions. Today’s Topic: Redox

Bell Ringer ACS Practice for the Final Day…No time to play. Be seated and ready for instructions. Today’s Topic: Periodicity

Bell Ringer ACS Practice for the Final Day…No time to play. Be seated and ready for instructions. Today’s Topic: Lab Chemistry

ACS Exam Pick up your remote from the CPS bag. Be sure that it is YOUR number. Begin testing immediately. You may use: Paper to show your work and a NON-Programmable Calculator. No Cell Phones!

Bell Ringer Day 1 of 4 for our Calorimeter Lab You will use a hand out to begin writing up our Lab Log entry. I. Procedures…detailed by simplified (should have prediction prior to starting) II. Safety-MSDS is a good resource III. Data/Observation Table ready for collection IN PEN…Partners are fine to this point

Lab Day 2 of 4 Data Collection Before you can begin collecting data…you must have your lab book entry preapproved. I. Procedures-short and sweet but shouldn’t need the manual to know how to do the lab. WITH A Prediction! II. Safety section for chemicals and equipment we are using. MSDS is your BFF. III. Data/Observations (begin after approval)

Lab Day 3 of 4 Final Day for Calorimeter Data Collection! Remember a full lab report includes: Intro, Procedures, Safety, Data & Observations, Calculations & Results (excel graphs etc), Discussion of Results, References in ACS and Additional Questions. You will be submitting all 8 sections to me on Tuesday after the break. Paper copy submission please… No 3 rd Person! Individual work!

Lab Day 4 of 4 Final Day for Calorimeter Data Collection! Remember a full lab report includes: Intro, Procedures, Safety, Data & Observations, Calculations & Results (excel graphs etc), Discussion of Results, References in ACS and Additional Questions. You will be submitting all 8 sections to me on Tuesday after the break. Paper copy submission please… No 3 rd Person! Individual work!

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Finals Bell Ringer Pick up your remote, take out your calculator (no cell phones) & scratch paper. No personal periodic tables but the one in our test booklet or on the wall is fair game. Your grade is based on number correct so it is to your best interest to answer every question.