ADG SOV df SS Trt 3 0 035

FCR SOV df SS Trt 3 0. 183 0. 061 Error 16 0. 079

CRD; Completely Randomized Design การจดผงการทดลอง replications) (4 Treatments, 5 T 4 R 2 T

RCBD; Randomized Complete Block Design (4 Treatments, 5 Blocks) การจดผงการทดลอง Block 1 T 4

LS; Latin Square Design การจดผงการทดลอง LS) (4 x 4 Columns Rows 1 2 3

Mathematical model = µ + Ti + ir CRD: Xir RCBD: Xijr = µ

CRD RCBD LS SOV df Trt Trt 3 Block 3 Rows 3 Error 9

CRD SOV Trt df t-1 Error t(r-1) Total tr-1 ( xij)2 CF = N

RCBD SOV Trt df t-1 Block b-1 SS Ti 2 – CF b Bj

LS SOV df Trt t-1 Rows t-1 Columns t-1 SS Ti 2 – CF

ANOVA; CRD SOV df SS Trt 3 SSTrt MS F L 1: T 1

ANOVA SOV df SS MS Trt 3 73. 69 24. 56 16. 61 L

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ADG SOV df SS Trt 3 0. 035 0. 012 Error 16 0. 014 0. 0009 Total 0. 049 19 Duncan’s Number of Means(p) LSR. 05 LSR. 01 LSD. 05 =. 0403 LSD. 01 =. 0555 MS 2 3. 0403. 0422. 0555. 0579 F 13. 03** 4. 0435. 0594

t = LSD XA – XB 2 S 2/n LSD = t , df of error 2 S 2/n LSD = 2 * t , df of error S 2/n Duncan LSR = SSR * SE

FCR SOV df SS Trt 3 0. 183 0. 061 Error 16 0. 079 0. 005 Total 0. 261 19 Duncan’s Number of Means(p) LSR. 05 LSR. 01 LSD. 05 =. 094 LSD. 01 =. 129 MS 2. 094. 129 3. 099. 135 F 12. 40** 4. 101. 139

CRD; Completely Randomized Design การจดผงการทดลอง replications) (4 Treatments, 5 T 4 R 2 T 2 R 5 T 1 R 4 T 3 R 3 T 1 R 1 T 2 R 1 T 3 R 1 T 4 R 1 T 1 R 1 T 3 R 1 T 2 R 1 T 4 R 3 T 1 R 2 T 2 R 2 T 3 R 2 T 4 R 2 T 2 R 2 T 1 R 3 T 3 R 5 T 1 R 3 T 2 R 3 T 3 R 3 T 4 R 5 T 3 R 4 T 1 R 2 T 2 R 4 T 1 R 4 T 2 R 4 T 3 R 4 T 4 R 4 T 3 R 2 T 4 R 4 T 2 R 3 T 4 R 1 T 1 R 5 T 2 R 5 T 3 R 5 T 4 R 5

RCBD; Randomized Complete Block Design (4 Treatments, 5 Blocks) การจดผงการทดลอง Block 1 T 4 T 2 T 1 T 3 T 1 T 2 T 3 T 4 2 3 4 T 1 T 3 T 2 T 4 T 1 T 2 T 3 T 4 T 2 T 4 T 3 T 1 T 2 T 3 T 4 5 T 3 T 1 T 2 T 4 T 1 T 2 T 3 T 4

LS; Latin Square Design การจดผงการทดลอง LS) (4 x 4 Columns Rows 1 2 3 4 T 1 T 2 T 3 T 4 1 2 3 4 T 2 T 3 T 4 T 1 T 2 T 3 cycle สม column row สม 1 2 3 4 4 T 1 T 2 T 3 2 1 3 T 2 T 3 T 4 T 1 T 2 3 1 4 T 2 T 4 T 3 T 1 2 1 3 T 4 T 2 T 1 T 3 T 1 T 4 T 2 T 1 T 3 T 2 T 4 4 2

Mathematical model = µ + Ti + ir CRD: Xir RCBD: Xijr = µ + Ti + Bj + ijr LS: Xijk = µ + Ti + Rj + Ck + ijk CRD RCBD LS Error = Block + Error = Row + Column + Error

CRD RCBD LS SOV df Trt Trt 3 Block 3 Rows 3 Error 9 Columns 3 3 Error 12 3 Error Total 15 15 6 15

CRD SOV Trt df t-1 Error t(r-1) Total tr-1 ( xij)2 CF = N SS Ti 2 ri – CF SST – SSTrt Xij 2 – CF MS F St 2 S 2

RCBD SOV Trt df t-1 Block b-1 SS Ti 2 – CF b Bj 2 – CF t Error (t-1)(b-1) SST - อนๆ Total tb-1 ( xij)2 CF = N Xij 2 – CF MS F St 2 S 2

A B C D 2. 25 2. 05 1. 96 2. 07 block 1 2. 34 2. 07 1. 96 2. 14 block 2 2. 12 1. 91 2. 00 2. 17 block 3 2. 31 2. 09 2. 12 block 4

LS SOV df Trt t-1 Rows t-1 Columns t-1 SS Ti 2 – CF t R j 2 t – CF Ck 2 – CF t Error (t-1)(t-2) SST - อนๆ Total t 2 -1 ( xij)2 CF = N Xij 2 – CF MS F St 2 S 2

ANOVA; CRD SOV df SS Trt 3 SSTrt MS F L 1: T 1 vs. (T 2+T 3+T 4) 1 SS(L 1) S 12 /S 2 L 2: T 4 vs. (T 2+T 3) 1 SS(L 2) S 22 /S 2 L 3: T 2 vs. T 3 1 SS(L 3) S 32 /S 2 Error 12 SSE Total 15 SST S 2 การสรปผลและแปลความหมายใหดคาเฉลยประกอบกบผลจา ก ANOVA

T 1 12 14 11 13 T 2 9 8 10 8 T 3 10 11 9 8 T 4 8 7 5 6 -3 0 0 +1 -1 -1 +1 +1 +2 0 Total 50 Mean 12. 5 คาสมประส ทธ 1 2 3 35 8. 75 38 9. 5 26 6. 5 L 1 L 2 L 3 ) Ti * Ci)2 ((50*-3)+ (35*+1) + (38*+1) + (26*+1))2 SS (L 1) = = ri Ci 2 4 (9+1+1+1) = 54. 1875

ANOVA SOV df SS MS Trt 3 73. 69 24. 56 16. 61 L 1: T 1 vs. (T 2+T 3+T 4) 1 54. 19 . . 36. 63** L 2: T 4 vs. (T 2+T 3) 1 18. 38 . . 12. 42** L 3: T 2 vs. T 3 1 1. 13 . . 0. 76 ns Error 12 17. 75 1. 48 Total 15 91. 44 F. 05, 1, 12 = 4. 75 F. 01, 1, 12 = 9. 33 F