Activity 2 Pythagoras Theorem Class 10 th Prepared

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Activity- 2 Pythagoras Theorem Class 10 th Prepared & Presented By Mrs. Pramila Kumari

Activity- 2 Pythagoras Theorem Class 10 th Prepared & Presented By Mrs. Pramila Kumari Sahoo TGT, Mathematics JNV, Jagatsinghpur, Odisha

Objective To verify Pythagoras theorem by performing an activity The area of the square

Objective To verify Pythagoras theorem by performing an activity The area of the square constructed on the hypotenuse of a rightangled triangle is equal to the sum of the areas of squares constructed on the other two sides of a rightangled triangle.

Materials Required • • Colored Papers • Sketch Pens Pair of Scissor • Light

Materials Required • • Colored Papers • Sketch Pens Pair of Scissor • Light colored square sheet Fevicol Geometry Box

Pre-requisite Knowledge • In a right-angled triangle the square of hypotenuse is equal to

Pre-requisite Knowledge • In a right-angled triangle the square of hypotenuse is equal to the sum of squares on the other two sides. • Concept of a right-angled triangle. • Area of square = (side)2 • Construction of perpendicular lines.

Procedure 1. Take a colored paper, draw and cut a right-angled triangle ACB right-angled

Procedure 1. Take a colored paper, draw and cut a right-angled triangle ACB right-angled at C, of sides 3 cm, 4 cm and 5 cm as shown in figure-1. Paste this triangle on a white sheet of paper. A 5 cm 4 cm C 3 cm Figure-1 B

2. Draw squares on each side of the triangle on side AB, BC and

2. Draw squares on each side of the triangle on side AB, BC and AC and name them accordingly G as shown in figure-2. A H F 4 cm I C 5 cm 3 cm B Figure-2 E D

3. Extend the line GA and FB such that they will meet HI and

3. Extend the line GA and FB such that they will meet HI and CE at P and Q respectively. Then draw a line PR from P, perpendicular to AP and meeting IC at R as shown in figure-3. G A H F 1 5 cm 4 cm P I 3 2 R C Q E 4 3 cm B 5 Figure-3 D

4. Cut the pieces 1, 2 and 3 from the square ACIH and 4

4. Cut the pieces 1, 2 and 3 from the square ACIH and 4 and 5 from square CBDE as shown in figue-4. G 4 A H 4 cm I 3 5. Then place the pieces on the square AGFB as shown and these pieces will completely cover its area. 3 2 5 cm 1 P 5 1 2 3 cm C B 4 Q E 5 Figure-4 D F

6. Alternate Method: Division of square ACIH can also be done in such a

6. Alternate Method: Division of square ACIH can also be done in such a way as shown in the figure-5, and the divided parts 1, 2, 3 and 4 can also be placed inside the larger square AGFB for the proof. G 2 A H 1 2 1 3 4 cm 4 I 5 3 m c 5 F 4 3 cm B C 5 E D Figure-5

Observation •

Observation •

Result Pythagoras theorem is verified.

Result Pythagoras theorem is verified.

k n a h T ou Y

k n a h T ou Y