Centripetal acceleration ac tangential acceleration is how fast the speed changes Centripetal acceleration is how fast the velocity changes because of its direction change.
Centripetal acceleration ac vf =vo +∆v vf = vo = v vf vo
Centripetal acceleration ac vf =vo +∆v vf = vo = v vo vf
Centripetal acceleration ac vf =vo +∆v vf vf = vo = v ∆v r q r s vf q vo
Centripetal acceleration ac vf ∆v r q r s vf q vo
Centripetal acceleration Inward
Tangential Acceleration tangential acceleration is how fast the speed changes change in speed a T= (time taken)
Fig. 4. 18, p. 94
Fig. 4. 19, p. 95
Fig. 4. 19 a, p. 95
Fig. 4. 19 b, p. 95
A car rounds a corner of radius 12. 0 m at a speed of 6 m/s while also pressing on the gas. If the car’s speed is increasing at a rate of 4 m/s^2, what is the magnitude of the car’s total acceleration?
While traveling due southward at a speed of 20 m/s a car’s acceleration is 6. 0 m/s^2 directed 60 degrees North of East. A) what is the radius of the car’s path? B) is the car speeding up or slowing down?
Betty Sue Pete VB/c=0 m/s Vs/g=0 ground VP/c=5 m/s conveyor Vc/g=10 m/s VP/g=? Fig. 4. 21, p. 96
Betty Sue VB/c=0 m/s Vs/g=0 ground Pete VP/c=5 m/s conveyor Vc/g=10 m/s VP/g= VP/c+ Vc/g=15 m/s Fig. 4. 21, p. 96
Betty Sue Pete VB/c=10 m/s Vs/g=0 ground VP/c=-5 m/s conveyor Vc/g=10 m/s VP/B=? Fig. 4. 21, p. 96
Betty Sue Pete VB/c=0 m/s Vs/g=-8 ground VP/c=5 m/s conveyor Vc/g=10 m/s VP/S=? Fig. 4. 21, p. 96
Betty Sue Pete VB/c=0 m/s Vs/g=-8 ground VP/c=5 m/s conveyor Vc/g=10 m/s VP/S= VP/c + Vc/g + Vg/S Fig. 4. 21, p. 96