9 3 Solving MultiStep Inequalities Math 9 We

  • Slides: 11
Download presentation
9. 3 Solving Multi-Step Inequalities Math 9

9. 3 Solving Multi-Step Inequalities Math 9

We can solve inequalities using the exact same methods learned in Chapter 8. Our

We can solve inequalities using the exact same methods learned in Chapter 8. Our goal is to ISOLATE the variable. ***REMEMBER to not forget how the inequality signs work when doing algebra steps!!! Recall some steps used to ISOLATE the variable:

Adding a positive number to both Multiply a positive number to sides… no change

Adding a positive number to both Multiply a positive number to sides… no change to the sign both sides… no change to the sign Subtract a positive number from Divide both sides by a positive both sides… no change to the sign number … no change to the sign Adding a negative number to both Multiply a negative number to sides… no change to the sign both sides… FLIP the sign Subtract a negative number from Divide both sides by a negative both sides… no change to the sign number … FLIP the sign

 • Solve each inequality and interpret the solution using a number line.

• Solve each inequality and interpret the solution using a number line.

1. 4 x + 11 > 35 -11 4 x >24 ÷ 4 X

1. 4 x + 11 > 35 -11 4 x >24 ÷ 4 X > 6 3 4 5 6 7 8 9

 • 2. 0 10 20 30 40 50 60

• 2. 0 10 20 30 40 50 60

3. 5 - 2 x > 10 x + 29 +2 x 5 >

3. 5 - 2 x > 10 x + 29 +2 x 5 > 12 x +29 -29 -24 > 12 x ÷ 12 -2 > x -5 -4 -3 -2 -1 0 1

4. 4( x -2) ≤ 5 x -12 Distribute the 4 into the brackets

4. 4( x -2) ≤ 5 x -12 Distribute the 4 into the brackets 4 x -8 ≤ 5 x - 12 -4 x -8 ≤ x -12 +12 4 ≤ x 0 1 2 3 4 5 6

Example 5 – Solving Problems Using Inequalities Danny has his own computer repair business.

Example 5 – Solving Problems Using Inequalities Danny has his own computer repair business. He offers his customers two payment options. Option A has a base fee of $40 plus $8 per hour. Option B has no base fee but costs $15 per hour. How many hours does a repair job have to take in order for option B to be less expensive? a) Model this problem using an inequality. Let h = hours on the job 40 + 8 h > 15 h b) After how many hours will option B be less expensive?

b) After how many hours will option B be less expensive? 40 + 8

b) After how many hours will option B be less expensive? 40 + 8 h > 15 h -8 h 40 > 7 h ÷ 7 5. 7 > h Therefore jobs shorter than 5. 7 hours will be less expensive with option B.

Time for 9. 3 Warm-up

Time for 9. 3 Warm-up