4 1 Maximum and Minimum Values Some of

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4. 1 Maximum and Minimum Values: Some of the most important applications of differential

4. 1 Maximum and Minimum Values: Some of the most important applications of differential calculus are optimization problems, where we are required to find the optimal (best) way of doing something. This can be done by finding the maximum or minimum values of a function. Absolute Extrema: highest and ______ lowest points on an interval. The _______

The Extreme Value Theorem: continuous on a closed interval [a, b] (1 st pic),

The Extreme Value Theorem: continuous on a closed interval [a, b] (1 st pic), then f has * if f is ________ BOTH a MINIMUM and MAXIMUM _______________________________

We can write an extrema (minima or maxima) in three different ways: 1) The

We can write an extrema (minima or maxima) in three different ways: 1) The absolute maximum occurs at the point (3, 5) 2) The absolute maximum is f (3) = 5 (the y-value or function value) 3) The absolute maximum occurs when x = 3. Extrema are _______!!! y - values

f (c) local max & absolute max f (d) local min & absolute min

f (c) local max & absolute max f (d) local min & absolute min f (d) absolute min f (c 1) & f (c 2) local max & absolute max f (d) local min & absolute min No max or min f (2) absolute min

EX #1 For each of the numbers a – e, state whether the function

EX #1 For each of the numbers a – e, state whether the function has a local min/max, absolute min/max, or neither. a. __________ Absolute min only b. __________ Local max c. __________ Local min Absolute max & d. __________ Local min e. __________ Local max

Fermat’s Theorem: If f has a local maximum or minimum at c, and if

Fermat’s Theorem: If f has a local maximum or minimum at c, and if f’(c) exists, then f’(c) = 0. EX #2: Find the extrema of Find f’ and set = 0. Test values on both sides of 0 for local extrema. Local minimum at (0, 0) Test 0 on the entire domain for absolute extrema. Absolute minimum at (0, 0) EX #3: Find the extrema of Find f’ and set = 0. Test values on both sides of 0 for local extrema. NO Local min or max at (0, 0) Test 0 on the entire domain for absolute extrema. NO Absolute min or max at (0, 0)

Find the y-coords. of these x-coords and the x-coords of the given interval. Absolute

Find the y-coords. of these x-coords and the x-coords of the given interval. Absolute max only Local min Local max Local min & Absolute min Neither

Critical Numbers: * Let f be defined at c. f’(c) = 0 or f’(c)

Critical Numbers: * Let f be defined at c. f’(c) = 0 or f’(c) = DNE (zeros on top and/or bottom) at c, then c is a _______ critical number of f. If ___________ ONLY OCCUR RELATIVE EXTREMA __________ AT CRITICAL NUMBERS!!! endpoints critical number ABSOLUTE EXTREMA can occur at ________ AND ________

Find f’ and set = 0. Product Rule. Critical numbers are 3/2 and 0.

Find f’ and set = 0. Product Rule. Critical numbers are 3/2 and 0.

EX #5: Find f’ and set = 0. Product Rule. Critical numbers are 4

EX #5: Find f’ and set = 0. Product Rule. Critical numbers are 4 and 0.

To find Absolute extrema (Abs. max/min) on a closed interval: 1. find the critical

To find Absolute extrema (Abs. max/min) on a closed interval: 1. find the critical numbers of f 2. evaluate f at each critical number 3. evaluate f at the endpoints 4. lowest value = absolute min; highest value = absolute max

* where does f’(x) = 0 and DNE: * evaluate critical numbers and endpoints:

* where does f’(x) = 0 and DNE: * evaluate critical numbers and endpoints: Absolute min Absolute max

EX #6: differentiate: where does f’(x) = 0 and DNE: evaluate critical numbers and

EX #6: differentiate: where does f’(x) = 0 and DNE: evaluate critical numbers and endpoints: Absolute min Absolute max

EX #6: differentiate: where does f’(x) = 0 and DNE: evaluate critical numbers and

EX #6: differentiate: where does f’(x) = 0 and DNE: evaluate critical numbers and endpoints: Absolute max Absolute min

differentiate: where does V’(T) = 0 and DNE: Quadratic Formula evaluate critical numbers and

differentiate: where does V’(T) = 0 and DNE: Quadratic Formula evaluate critical numbers and endpoints: Since our temperature has the given interval, 0 < T < 30, 79. 5 is out. Absolute min