12 5 Parabolas Warm Up Lesson Presentation Lesson

12 -5 Parabolas Warm Up Lesson Presentation Lesson Quiz Holt. Mc. Dougal Algebra 2 Holt

12 -5 Parabolas Warm Up 1. Given , solve for p when c = Find each distance. 2. from (0, 2) to (12, 7) 13 3. from the line y = – 6 to (12, 7) 13 Holt Mc. Dougal Algebra 2

12 -5 Parabolas Objectives Write the standard equation of a parabola and its axis of symmetry. Graph a parabola and identify its focus, directrix, and axis of symmetry. Holt Mc. Dougal Algebra 2

12 -5 Parabolas Vocabulary focus of a parabola directrix Holt Mc. Dougal Algebra 2

12 -5 Parabolas In Chapter 5, you learned that the graph of a quadratic function is a parabola. Because a parabola is a conic section, it can also be defined in terms of distance. Holt Mc. Dougal Algebra 2

12 -5 Parabolas A parabola is the set of all points P(x, y) in a plane that are an equal distance from both a fixed point, the focus, and a fixed line, the directrix. A parabola has a axis of symmetry perpendicular to its directrix and that passes through its vertex. The vertex of a parabola is the midpoint of the perpendicular segment connecting the focus and the directrix. Holt Mc. Dougal Algebra 2

12 -5 Parabolas Remember! The distance from a point to a line is defined as the length of the line segment from the point perpendicular to the line. Holt Mc. Dougal Algebra 2

12 -5 Parabolas Example 1: Using the Distance Formula to Write the Equation of a Parabola Use the Distance Formula to find the equation of a parabola with focus F(2, 4) and directrix y = – 4. PF = PD Definition of a parabola. Distance Formula. Substitute (2, 4) for (x 1, y 1) and (x, – 4) for (x 2, y 2). Holt Mc. Dougal Algebra 2

12 -5 Parabolas Example 1 Continued Simplify. (x – 2)2 + (y – 4)2 = (y + 4)2 Square both sides. (x – 2)2 + y 2 – 8 y + 16 = y 2 + 8 y + 16 Expand. 2 Subtract y and 16 2 (x – 2) – 8 y = 8 y from both sides. (x – 2)2 = 16 y Add 8 y to both sides. Solve for y. Holt Mc. Dougal Algebra 2

12 -5 Parabolas Check It Out! Example 1 Use the Distance Formula to find the equation of a parabola with focus F(0, 4) and directrix y = – 4. PF = PD Definition of a parabola. Distance Formula Substitute (0, 4) for (x 1, y 1) and (x, – 4) for (x 2, y 2). Holt Mc. Dougal Algebra 2

12 -5 Parabolas Check It Out! Example 1 Continued Simplify. x 2 + (y – 4)2 = (y + 4)2 Square both sides. x 2 + y 2 – 8 y + 16 = y 2 + 8 y +16 Expand. 2 x – 8 y = 8 y x 2 = 16 y Subtract y 2 and 16 from both sides. Add 8 y to both sides. Solve for y. Holt Mc. Dougal Algebra 2

12 -5 Parabolas Previously, you have graphed parabolas with vertical axes of symmetry that open upward or downward. Parabolas may also have horizontal axes of symmetry and may open to the left or right. The equations of parabolas use the parameter p. The |p| gives the distance from the vertex to both the focus and the directrix. Holt Mc. Dougal Algebra 2

12 -5 Parabolas Holt Mc. Dougal Algebra 2

12 -5 Parabolas Example 2 A: Writing Equations of Parabolas Write the equation in standard form for the parabola. Step 1 Because the axis of symmetry is vertical and the parabola opens downward, the equation is in the form y= Holt Mc. Dougal Algebra 2 1 4 p x 2 with p < 0.

12 -5 Parabolas Example 2 A Continued Step 2 The distance from the focus (0, – 5) to the vertex (0, 0), is 5, so p = – 5 and 4 p = – 20. Step 3 The equation of the parabola is y = – Check Use your graphing calculator. The graph of the equation appears to match. Holt Mc. Dougal Algebra 2 1 20 x 2.

12 -5 Parabolas Example 2 B: Writing Equations of Parabolas Write the equation in standard form for the parabola. vertex (0, 0), directrix x = – 6 Step 1 Because the directrix is a vertical line, the equation is in the form . The vertex is to the right of the directrix, so the graph will open to the right. Holt Mc. Dougal Algebra 2

12 -5 Parabolas Example 2 B Continued Step 2 Because the directrix is x = – 6, p = 6 and 4 p = 24. Step 3 The equation of the parabola is x = Check Use your graphing calculator. Holt Mc. Dougal Algebra 2 1 24 y. 2

12 -5 Parabolas Check It Out! Example 2 a Write the equation in standard form for the parabola. vertex (0, 0), directrix x = 1. 25 Step 1 Because the directrix is a vertical line, the equation is in the form of . The vertex is to the left of the directrix, so the graph will open to the left. Holt Mc. Dougal Algebra 2

12 -5 Parabolas Check It Out! Example 2 a Continued Step 2 Because the directrix is x = 1. 25, p = – 1. 25 and 4 p = – 5. Step 3 The equation of the parabola is Check Use your graphing calculator. Holt Mc. Dougal Algebra 2

12 -5 Parabolas Check It Out! Example 2 b Write the equation in standard form for each parabola. vertex (0, 0), focus (0, – 7) Step 1 Because the axis of symmetry is vertical and the parabola opens downward, the equation is in the form Holt Mc. Dougal Algebra 2

12 -5 Parabolas Check It Out! Example 2 b Continued Step 2 The distance from the focus (0, – 7) to the vertex (0, 0) is 7, so p = – 7 and 4 p = – 28. Step 3 The equation of the parabola is Check Use your graphing calculator. Holt Mc. Dougal Algebra 2

12 -5 Parabolas The vertex of a parabola may not always be the origin. Adding or subtracting a value from x or y translates the graph of a parabola. Also notice that the values of p stretch or compress the graph. Holt Mc. Dougal Algebra 2

12 -5 Parabolas Holt Mc. Dougal Algebra 2

12 -5 Parabolas Example 3: Graphing Parabolas Find the vertex, value of p, axis of symmetry, focus, and directrix of the parabola y + 3 = 1 (x – 2)2. Then graph. 8 Step 1 The vertex is (2, – 3). Step 2 1 4 p Holt Mc. Dougal Algebra 2 = 1 , so 4 p = 8 and p = 2. 8

12 -5 Parabolas Example 3 Continued Step 3 The graph has a vertical axis of symmetry, with equation x = 2, and opens upward. Step 4 The focus is (2, – 3 + 2), or (2, – 1). Step 5 The directrix is a horizontal line y = – 3 – 2, or y = – 5. Holt Mc. Dougal Algebra 2

12 -5 Parabolas Check It Out! Example 3 a Find the vertex, value of p, axis of symmetry, focus, and directrix of the parabola. Then graph. Step 1 The vertex is (1, 3). Step 2 1 4 p = 1 , so 4 p = 12 and p = 3. Holt Mc. Dougal Algebra 2 12

12 -5 Parabolas Check It Out! Example 3 a Continued Step 3 The graph has a horizontal axis of symmetry with equation y = 3, and opens right. Step 4 The focus is (1 + 3, 3), or (4, 3). Step 5 The directrix is a vertical line x = 1 – 3, or x = – 2. Holt Mc. Dougal Algebra 2

12 -5 Parabolas Check It Out! Example 3 b Find the vertex, value of p axis of symmetry, focus, and directrix of the parabola. Then graph. Step 1 The vertex is (8, 4). Step 2 1 4 p Holt Mc. Dougal Algebra 2 1 = – 1 , so 4 p = – 2 and p = –. 2 2

12 -5 Parabolas Check It Out! Example 3 b Continued Step 3 The graph has a vertical axis of symmetry, with equation x = 8, and opens downward. Step 4 The focus is or (8, 3. 5). Step 5 The directrix is a horizontal line or y = 4. 5. Holt Mc. Dougal Algebra 2

12 -5 Parabolas Light or sound waves collected by a parabola will be reflected by the curve through the focus of the parabola, as shown in the figure. Waves emitted from the focus will be reflected out parallel to the axis of symmetry of a parabola. This property is used in communications technology. Holt Mc. Dougal Algebra 2

12 -5 Parabolas Example 4: Using the Equation of a Parabola The cross section of a larger parabolic microphone can be modeled by the equation 1 2 What is the length yof x=. the feedhorn? 132 The equation for the cross section is in the form x= 1 4 p y 2, so 4 p = 132 and p = 33. The focus should be 33 inches from the vertex of the cross section. Therefore, the feedhorn should be 33 inches long. Holt Mc. Dougal Algebra 2

12 -5 Parabolas Check It Out! Example 4 Find the length of the feedhorn for a microphone with a cross section equation x = 1 y 2. 44 The equation for the cross section is in the form x= 1 4 p y 2, so 4 p = 44 and p = 11. The focus should be 11 inches from the vertex of the cross section. Therefore, the feedhorn should be 11 inches long. Holt Mc. Dougal Algebra 2

12 -5 Parabolas Lesson Quiz 1. Write an equation for the parabola with focus F(0, 0) and directrix y = 1. 2. Find the vertex, value of p, axis of symmetry, focus, 1 and directrix of the parabola y – 2 = (x – 4)2, 12 then graph. vertex: (4, 2); focus: (4, 5); directrix: y = – 1; p = 3; axis of symmetry: x = 4 Holt Mc. Dougal Algebra 2