12 2 Surface Area of Prisms and Cylinders

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12. 2 Surface Area of Prisms and Cylinders

12. 2 Surface Area of Prisms and Cylinders

Types of Polyhedra: • Prism: 3 -D figure with two identical parallel faces –

Types of Polyhedra: • Prism: 3 -D figure with two identical parallel faces – The bases are congruent, parallel faces – A prism is named by the shape of its base – Lateral faces are all faces excluding bases (rectangle)

Some examples: • Rectangular Prism or right prism:

Some examples: • Rectangular Prism or right prism:

 • Triangular Prism:

• Triangular Prism:

 • Pentagonal Prism:

• Pentagonal Prism:

 • Hexagonal Prism:

• Hexagonal Prism:

 • Pyramid: 3 -D figure with one base – A pyramid is named

• Pyramid: 3 -D figure with one base – A pyramid is named by the shape of its bases – Faces are triangles

Some examples: • Square Pyramid:

Some examples: • Square Pyramid:

 • Triangular Pyramid

• Triangular Pyramid

 • Pentagonal Pyramid:

• Pentagonal Pyramid:

Other 3 -Dimensional figures-have curved faces • Cylinder: 2 congruent parallel bases

Other 3 -Dimensional figures-have curved faces • Cylinder: 2 congruent parallel bases

 • Cone: has one circular base and one vertex

• Cone: has one circular base and one vertex

 • Net: 2 -D pattern that when folded is 3 -D – Dotted

• Net: 2 -D pattern that when folded is 3 -D – Dotted lines indicate folds rectangular prism square pyramid

 • Surface Area: sum of the areas of the faces of the solid/polyhedron

• Surface Area: sum of the areas of the faces of the solid/polyhedron – Surface area is measured in square units Surface Area of a Right Prism: S = 2 B + Ph B- area of the base P- perimeter of the base h- height

 • Active Inspire for examples!

• Active Inspire for examples!

Find the surface area of the right prism 12 in B C A 15

Find the surface area of the right prism 12 in B C A 15 in 30 in S = 2 B + Ph S = 2 (30 15) + (90) 12 S = 900 + 1080 S = 1980 in²

 • Surface Area of a Right Cylinder: S = 2 B + Ch

• Surface Area of a Right Cylinder: S = 2 B + Ch B- area of the base C- circumference h- height

 • Active Inspire for examples

• Active Inspire for examples

4 cm S = 2 B + Ch S = 2(π 4²) + (2π

4 cm S = 2 B + Ch S = 2(π 4²) + (2π 4) 9 9 cm S = 100. 53 + 226. 19 S = 326. 72 cm²