1 A 4 Factoring Square Root Method Trinomial

1 A. 4 Factoring üSquare Root Method üTrinomial Method when a = 1 üGCF

Solving with Square Roots 1. Get x 2 or the binomial squared by itself 2. Take the square root of BOTH sides of the equal sign 3. Don’t forget the sign 4. Simplify *if the square term is inside ( ), distribute, if it's outside DON'T

Solve by Taking Square Roots X = ± 2 i

Solve by Taking Square Roots

Solve by Taking Square Roots

Solve by Taking Square Roots

Solve by Taking Square Roots 5. 5(x – 2 4) = 125 X = -1 and 9

Solve by Taking Square Roots

Solve by Taking Square Roots 7. - 2 9 x = 243

Solve by Factoring (a=1) Standard Form of a Quadratic Equation: ax 2 + bx + c = 0 1. Put the equation in descending order from highest power to lowest power. 2. List all the factors of c. 3. Determine which factors of c when added together equal b. 4. Create two binomials with the variable as the first term and set it equal to zero… (x )= 0 5. Write in the factors that you determined from step 3. 6. Set each binomial equal to zero and solve each one for your variable.

Solve by Factoring (a=1) 1. 8 x + x 2 + 7 = 0 x = -7 x = -1

Solve by Factoring (a=1) 4. x 2 – x – 56 = 0 x = -7 x = 8

Solve by Factoring (a=1) 2. n 2 – 11 n + 10 = 0 n = 1

Solve by Factoring (a=1) 3. m 2 + m – 90 = 0 m = 9 m = -10

Solve by Factoring (a=1) 5. x 2 – 5 x – 104 = 0 x = -8 x = 13

Solve by Factoring When There is a Greatest Common Factor(GCF) Standard Form of a Quadratic Equation: ax 2 + bx + c = 0 1. When a > 1, examine the factors of a, b and c to determine if there is a GCF (the largest number that a, b & c can all be divided by). 2. Divide each term of the quadratic equation by the GCF. 3. Put the GCF in front and the new trinomial from step 2 in parentheses, and set it equal to zero. 4. Factor the trinomial like normal.

Solve by Factoring (GCF) 1. 2 x 2 + 6 x – 108 = 0 x = -9 x = 6

Solve by Factoring (GCF) 2. 3 x 2 + 9 x – 54 = 0 x = -6 x = 3